What is the derivative of #g(x)=sqrt(5-3x)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Alan N. Jul 5, 2016 #-3/(2sqrt(5-3x))# Explanation: The chain rule states: #d/dx(g(f(x)) = g'(f(x)) * f'(x)# In this example #g(x) = (5-3x)^(1/2)# #-> f(x) = 5-3x# Thus #d/dx(g(x)) = 1/2 (5-3x)^(-1/2) * -3# #= -3/(2sqrt(5-3x))# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1255 views around the world You can reuse this answer Creative Commons License