How do you find the second derivative of ln(x/2) ? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Ratnaker Mehta Jul 6, 2016 :. (d^2y)/dx^2=-1/x^2 Explanation: Let y=ln(x/2) We have to find (d^2y)/dx^2. We start with y=ln(x/2) and use Rules of Logarithmic Fun. to see that, y=lnx-ln2 :. (dy)/dx=1/x=x^-1. :. (d^2y)/dx^2=d/dx{dy/dx}....[Defn.] = d/dx(x^-1)=-1*x^(-1-1). :. (d^2y)/dx^2=-1/x^2. Answer link Related questions What is the derivative of f(x)=ln(g(x)) ? What is the derivative of f(x)=ln(x^2+x) ? What is the derivative of f(x)=ln(e^x+3) ? What is the derivative of f(x)=x*ln(x) ? What is the derivative of f(x)=e^(4x)*ln(1-x) ? What is the derivative of f(x)=ln(x)/x ? What is the derivative of f(x)=ln(cos(x)) ? What is the derivative of f(x)=ln(tan(x)) ? What is the derivative of f(x)=sqrt(1+ln(x) ? What is the derivative of f(x)=(ln(x))^2 ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 1546 views around the world You can reuse this answer Creative Commons License