Question

How do you find the nature of the roots using the discriminant given `2x^2 + 7x - 3 = 0`?

Answer 1

The roots are real: `0.386 , -3.886`

Explanation:

Here in the quadratic equation of form `ax^2+bx+c; a=2 ; b=7;c=-3 :.`Discriminant `d=b^2-4ac =7^2-(4*2*(-3))=73` since `d>0` the roots are real. Roots`= (-b+-sqrt(b^2-4ac))/(2a) :.`root1`= (-7+sqrt73)/4=0.386` and root2 `=(-7-sqrt73)/4= -3.886`[Ans]