How do you prove #log_(b^n)(x^n)=log_(b)x#? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer Cesareo R. Jul 6, 2016 See below Explanation: #log_a b = log_x a/(log_x b)# so #log_(b^n)(x^n)=log_ex^n/(log_e b^n) = (n log_e x)/(n log_e b) = (log_e x)/(log_e b) = log_b x# Answer link Related questions What is the exponential form of #log_b 35=3#? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is #log_b 1#? What are some identity rules for logarithms? What is #log_b b^x#? What is the reciprocal of #log_b a#? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 1691 views around the world You can reuse this answer Creative Commons License