How do you differentiate #f(x)= x/(x^3-4 )# using the quotient rule? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Alexander Jul 8, 2016 Using the quotient rule on #f(x) = (x)/(x^3-4)#, which states that if #f(x)=##a(x)##/##b(x)#, then #f'(x)=[b(x)*a'(x)-a(x)*b'(x)]/[(b(x))^2]# Let #b(x) = x^3-4# and #a(x) = x#, so #f'(x) = [(x^3-4) - (3x^3)]/[(x^3-4)^2]# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 1268 views around the world You can reuse this answer Creative Commons License