How do you differentiate # F(x) = 3x^2 + 12#?

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Answer 1 · 2016-07-08T08:25:10

Using the power rule on #F(x) = 3x^2+12#, which states that #d/dx[x^n] = n*x^(n-1)#, you get #F'(x) = 6x#.