How do you find the inverse of #y=ln(x+1)#?

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Answer 1 · 2016-07-09T04:17:23

The inverse is found algebraically by switching the x and y values.

#y = ln(x + 1)#

#x = ln(y + 1)#

#e^x = y + 1#

#y = e^x - 1#

Practice exercises:

#y = 2^(x - 5)#

#y = (x - 2)^3 + 6#

#y = root(4)(x^2 + 7) - 1#

Hopefully this helps, and good luck!