What is #a_1# and #d# for an arithmetic sequence with #a_3 = -8# and #a_7=32#?

1 Answer
Jul 9, 2016

Different people have different ways of attacking such problems but my method involves systems of equations.

Recall the nth term of an arithmetic sequence is given by #t_n = a + (n - 1)d#. Then:

#32 = a + (7 - 1)d#
#-8 = a + (3 - 1)d#

Solving for #a# and for #d#:

#32 = a + 6d#

#32 - 6d = a#

#-8 = 32 - 6d + 2d#

#-8 - 32 = -4d#

#-40 = -4d#

#10 = d#

We can now use the formula #t_n = a + (n - 1)d# to find #a#

#-8 = a + (3 - 1)10#

#-8= a + 20#

#-8 - 20 = a#

#a = -28#

In summary...

#d = 10#

#a = -28#

Practice exercises:

  1. If in an arithmetic sequence the fifth term has a value of #3# and the sixteenth term has a value of #-41#, determine:

a) #d#

b) #t_75#

c) #s_26#

Hopefully this helps, and good luck!