Question

Question #7c5e0

Answer 1

Given

`f="The focal length of convex mirror"= 20 cm`

`u="Object distance"=-6m=-600 cm`

`v="Image distance"=?`

`h_o="Height of the object"1.6m`

`w_o="Width of the object"=2m`

`color(blue)("The Mirror Formula":`

`color(red)(1/v+1/u=1/f)`

`=>1/v-1/600=1/20`

`=>1/v=1/20+1/600=31/600`

`=>v=600/31~~20cm`

`m="Magnification"=-v/u=1/31`

So

`h_i="Height of the image"=mxxh_o=160/31cm`

`h_i="Width of the image"=mxxw_o=200/31cm`

So the image of the car will be seen `~~20 cm` behind the mirror and its height will be `160/31cm` and its width will be `200/31cm`