Question

How do you find the derivative of `y= (x+1) / (x-1)`?

Answer 1

`= -( 2 )/((x-1)^2)`

Explanation:

Quotient Rule

`(u/v)^prime = (u' v - u v')/(v^2)`

here `u = x+1, v = x-1, u' = v' = 1`

so we have

`((1) (x-1) - (x+1) (1))/((x-1)^2)`

`= -( 2 )/((x-1)^2)`