How do you solve #arctan(2x)= -1#?

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Answer 1 · 2016-07-10T16:09:08

#x=-1/2 radian#, assuming that angular measure is in radian unit.

So,# tan (2x)=tan(-1)#, and so,

the principal value of 2x = -1 radian

#x=-1/2# radian .

For the general value, #2x = npi-1# and

# x = (npi-1)/2 radians, n=0, +-1, +-2, +-3, ...#

1 radian = #(180/(pi)) ^o=57.3^o#, nearly.

Answer 2 · 2016-07-10T22:55:46

#28^@66#

arctan 2x = -1
#2x = -1 rad. = 180^@/(3.14) = 57^@32#
#x = 28^@66#