Question

How do you differentiate `tan(sqrt(2x+5))`?

Answer 1

`d y=(1+tan^2(sqrt(2x+5)))/(sqrt(2x+5)) * d x`

Explanation:

`y=tan sqrt(2x+5)`

`"let's use the chain rule"`

`d y=(1+tan^2sqrt(2x+5))* cancel(2)/ (cancel(2)*sqrt((2x+5))) d x`

`d y=(1+tan^2(sqrt(2x+5)))/(sqrt(2x+5)) * d x`