How do you factor #(a+b)^4 - (a-b)^4#?

1 Answer
Jul 14, 2016

=#4ab[(a+b)^2+ (a-b)^2]#

Explanation:

This is easier than it seems at first glance.
DO NOT multiply out the brackets - that will only make things worse!

This expression is written in the form #x^2 - y^2# which is difference of 2 squares.

Let (a+b) be #x# and (a-b) be #y#, just to make it easier to work with.

#x^4 - y^4# is also the difference of squares. #(x^2)^2 = x^4#

=#(x^2 + y^2)(x^2-y^2)#

=#color(blue)((x^2 + y^2))color(red)((x+y))color(orange)((x-y))" replace " x and y #

=#color(blue)([(a+b)^2+ (a-b)^2])color(red)([(a+b) +(a-b)])color(orange)([(a+b)- (a-b)])#

#color(blue)([(a+b)^2+ (a-b)^2])color(red)([(2a)color(orange)((2b))])#
=#4ab[(a+b)^2+ (a-b)^2]#