How do you solve 4y+4x=0 and -y-2=x?

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Answer 1 · 2016-07-16T08:50:59

This set of equations has no solutions.

We start with the following set:

#{(4y+4x=0),(-y-2=x):}#

If we divide the first equation by #4# we get: #y+x=0#.
The second equation can be transformed to: #y+x=-2#, so we get the system:

#{(y+x=0),(y+x=-2):}#

If we substract both sides of the second equation from the respective sides of the first we get:

#0=2#

which is false and means that the set has no solutions.