How do you find all the zeros of F(x)=x4−13x2+36?
1 Answer
Jul 16, 2016
Zeros:
Explanation:
Since there are no terms of odd degree, we can treat this as a quadratic in
First note that
x4−13x2+36
=(x2)2−13(x2)+36
=(x2−9)(x2−4)
=(x2−32)(x2−22)
=(x−3)(x+3)(x−2)(x+2)
Hence zeros:
±3 ,±2