How do you solve #4=(5z+2)/3#?

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Answer 1 · 2016-07-17T01:35:01

#color(green)(z = 2")#

#color(indigo)("Multiply 3 on both sides to get rid of the denominator:")#

#4xx3=(5z+2)/cancel3##xxcancel3#

#color(hotpink)("Subtract 2 on both sides to get the constant by itself:")#

#12 = 5z+2#
#-2 color(white)(aaaa) -2#

#10=5z#

#color(green)("Divide both sides by 5 to find z:")#
#10/5=(cancel5z)/cancel5#

#2=z#