Question

How do you solve `Cos x / (1- sin x) = sec x + tan x`?

Answer 1

`(cosx)/(1-sinx) *(cosx)/cosx`
`=(cos^2x)/((1-sinx)cosx)`
`=(sin^2x-1)/((1-sinx)cosx)`
`=((1+sinx)cancel((1-sinx)))/(cancel((1-sinx))cosx)`
`=1/cosx +(sinx)/cosx`
`=secx +tanx`