Question

How do you express `(x^2 - 4) / (x -1)` in partial fractions?

Answer 1

`(x^2-4)/(x-1)=x+1-3/(x-1)`

Explanation:

`(x^2-4)/(x-1)`

= `(x^2-1-3)/(x-1)`

= `(x^2-1)/(x-1)-3/(x-1)`

= `((x-1)(x+1))/(x-1)-3/(x-1)`

= `x+1-3/(x-1)`