Question

How do you solve `x^2 = 5x +2`?

Answer 1

`x=(10+sqrt(33))/2, (10 -sqrt(33))/2`

Explanation:

`x^2-5x-2=0`

then use the qudratic formula

`x=5+-sqrt(5^2-(4*1*-2))/(2*1)`
`x=5+-sqrt(33)/(2)`
`x=(10+sqrt(33))/2, (10 -sqrt(33))/2`