Question

How do you integrate `int (x-2x^2)/((x-6)(x-2)(x-5))` using partial fractions?

Answer 1

Divide by `x-2` first

Explanation:

`x/[(x-6)(x-5)] = x[1/(x-6) - 1/(x-5)]`
`= 6/(x-6) - 5/(x-5)`
And the integral I is
`6 log |x-6| - 5 log|x-5|`