What is the derivative of #e^(2x)/x#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Base e 1 Answer Eddie Jul 20, 2016 # =e^(2x) ((2 x - 1)/(x^2))# Explanation: so why not use the quotient rule #(u/v)' = (u' * v - u * v')/(v^2)# # = (2e^(2x) * x - e^(2x) (1))/(x^2)# # =e^(2x) ((2 x - 1)/(x^2))# Answer link Related questions What is the derivative of #y=3x^2e^(5x)# ? What is the derivative of #y=e^(3-2x)# ? What is the derivative of #f(theta)=e^(sin2theta)# ? What is the derivative of #f(x)=(e^(1/x))/x^2# ? What is the derivative of #f(x)=e^(pix)*cos(6x)# ? What is the derivative of #f(x)=x^4*e^sqrt(x)# ? What is the derivative of #f(x)=e^(-6x)+e# ? How do you find the derivative of #y=e^x#? How do you find the derivative of #y=e^(1/x)#? How do you find the derivative of #y=e^(2x)#? See all questions in Differentiating Exponential Functions with Base e Impact of this question 6465 views around the world You can reuse this answer Creative Commons License