How do you solve #2x^2-3x=-4# using the quadratic formula?
1 Answer
Jul 21, 2016
No real roots
Explanation:
Use the new improved quadratic formula (Socratic Search)
y = 2x^2 - 3x + 4 = 0
D = d^2 = b^2 - 4ac = 9 - 32 = - 23.
Because D < 0, there are no real roots. There are 2 complex roots.
