How do you differentiate #y=e^((2x)/3)#?
1 Answer
Jul 21, 2016
Explanation:
#color(orange)"Reminder"#
#d/dx(e^x)=e^x# and using the
#color(blue)"chain rule"#
#color(red)(|bar(ul(color(white)(a/a)color(black)(d/dx(e^(g(x)))=e^(g(x))g'(x))color(white)(a/a)|)))#
#rArrdy/dx=e^((2x)/3).d/dx(2/3x)=2/3e^((2x)/3)#
