How do you evaluate 6C3?

1 Answer
Shwetank Mauria
Jul 21, 2016

""^6C_3=20

Explanation:

""^nC_r is selection of r possible combinations of objects from a set of n objects.

Mathematically ""^nC_r=(n!)/(r!xx(n-r)!)

Hence ""^6C_3=(6!)/(3!xx(6-3)!)

= (6xx5xx4xx3xx2xx1)/((3xx2xx1)xx(3xx2xx1))

= (6xx5xx4)/(3xx2xx1)=5xx4=20

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