How do you differentiate f(x)=(2x+3)^4 / x using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Abhinav T. Jul 21, 2016 d/dx (f(x)) = d/dx ((2x+3)^4/x) Or, f'(x) = 1/x * d/(d(2x+3)) (2x+3)^4* d/dx (2x+3) + (2x+3)^4 d/dx (1/x) =1/x * 4 (2x+3)^3 * 2- (2x+3)^4/x^2 =(8x (2x+3)^3-(2x+3)^4)/x^2 =(2x+3)^3(8x-2x-3)/x^2 = 3 (2x+3)^3 * (2x -1) / x^2 Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 2194 views around the world You can reuse this answer Creative Commons License