How do you find the other five trigonometric values given cos t = 5/13 and sin t > 0? Trigonometry Right Triangles Relating Trigonometric Functions 1 Answer Deepak G. Jul 21, 2016 #sect=13/5#;#sint=12/13#;#cosect=13/12#;#tant =5/12##cott=12/5# Explanation: #cost =5/13# #sect=1/cost=13/5# #sint=sqrt(1-(5/13)^2)# or #sint=sqrt(1-25/169)# or #sint=sqrt((169-25)/169)# or #sint=sqrt(144/169)# or #sint=12/13# #cosect=1/sint=13/12# #tant =sint/cost = (5/13)/(12/13) =5/12# #cott=1/tant=12/5# Answer link Related questions What does it mean to find the sign of a trigonometric function and how do you find it? What are the reciprocal identities of trigonometric functions? What are the quotient identities for a trigonometric functions? What are the cofunction identities and reflection properties for trigonometric functions? What is the pythagorean identity? If #sec theta = 4#, how do you use the reciprocal identity to find #cos theta#? How do you find the domain and range of sine, cosine, and tangent? What quadrant does #cot 325^@# lie in and what is the sign? How do you use use quotient identities to explain why the tangent and cotangent function have... How do you show that #1+tan^2 theta = sec ^2 theta#? See all questions in Relating Trigonometric Functions Impact of this question 4328 views around the world You can reuse this answer Creative Commons License