How do you factor #9u^2+24uv+16v^2#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Ratnaker Mehta Jul 22, 2016 #(3u+4v)^2#. Explanation: Let us remember the Identity # : a^2+2ab+b^2=(a+b)^2#. Now, #9u^2+24uv+16v^2# #=(3u)^2+2*3u*4v+(4v)^2# #=(3u+4v)^2#. Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 2801 views around the world You can reuse this answer Creative Commons License