How do you evaluate #csc 0#? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Ratnaker Mehta Jul 22, 2016 #csc0# is undefined. Explanation: Remember that #csctheta=1/sintheta#. Now #sin0=0 rArr csc0# is undefined. In fact, the Domain of #csc# function is #RR-{kpi : k in ZZ}=RR-{0,+-pi,+-2pi,.................}#, so, #csc0# is not defined. Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 10632 views around the world You can reuse this answer Creative Commons License