Question

How do you find the domain and range of `h(x) = sqrt(x-3)`?

Answer 1

Domain is `[3,oo)`.

Range is `[0,oo)`.

Explanation:

In `RR`, negative nos. do not have square-root.

So, `(x-3)>=0, i.e., x>=3`. Hence, Domain is `[3,oo)`.

Also, square-root means `+ve` square-root, so, `h(x)>=0`

Hence, the Range is `[0,oo)`.