How do you solve #(x-3)/4=2#?

1 Answer
Jul 23, 2016

x = 11

Explanation:

If we multiply both sides of the equation by 4 then we eliminate the fraction.

#color(red)cancel(4)^1xx(x-3)/(color(red)cancel(4)^1)=color(red)(4)xx2#

we are now left with : x - 3 = 8

Add 3 to both sides to solve for x

#x-cancel(3)+cancel(3)=8+3#

#rArrx=11#