Question

Question #8908d

Answer 1

`secA=+-sqrt(a^2+b^2)/b`.

Explanation:

Though the Question is not clearly placed, but as I understand, it asks to find the value of `secA`, given the value of `cotA=a/b`.

So, we do it this way:-

`cotA=a/b rArr tanA=b/arArr sec^2A=1+tan^2A=1+b^2/a^2`

`=(a^2+b^2)/a^2`

`:. secA=+-sqrt(a^2+b^2)/b`.