How do you solve #12|x/4+11|= 60#?
1 Answer
Jul 25, 2016
x = - 24 , x = - 64
Explanation:
There are 2 parts to solve here.
First divide both sides by 12
#(cancel(12)^1|x/4+11|)/cancel(12)^1=60/12=5# (1) solve
#x/4+11=5rArrx/4=-6# multiply both sides by 4
#cancel(4)^1xxx/cancel(4)^1=-6xx4rArrx=-24# and (2) solve
#x/4+11=-5" and proceed as before"#
#rArrx/4=-16rArrx=-64# Thus solutions are x = -24 and x = -64