Question

How do you solve `2z^2 - 10z = -12`?

Answer 1

2 and 3

Explanation:

`y = 2z^2 - 10z + 12 = 0`
Use the improved quadratic formula in graphic form (Socratic Search)
`D = d^2 = b^2 - 4ac = 100 - 96 = 4` --> `d = +- 2`
There are 2 real roots:
`x = -b/(2a) +- d/(2a) = 10/4 +- 2/4`
`x = 5/2 +- 1/2 = (5 +- 1)/2 =`
`x1 = 6/2 = 3` and `x2 = 4/2 = 2`