How do you solve (8x)^(1/2)+6=0?
2 Answers
Jul 27, 2016
Explanation:
Get rid of 6 from left side
For that subtract 6 on both sides
Squaring on both sides
Jul 28, 2016
There are no values of
Explanation:
(8x)^(1/2)+6=0
Subtract
(8x)^(1/2) = -6
Square both sides, noting that squaring may introduce spurious solutions:
8x = 36
Divide both sides by
x = 36/8 = 9/2
Check:
(8x)^(1/2)+6 = (8*9/2)^(1/2)+6 = 36^(1/2)+6 = 6+6 = 12
So this
The problem is that while
So the original equation has no solutions (Real or Complex).