Question

What is the daughter nucleus (nuclide) produced when `""^64Cu` undergoes beta decay by emitting an electron?

Answer 1

`""^64Zn`

Explanation:

`""^64Cu` can decay in several ways, when it decays by emitting an electron (`beta^-` particle) the resulting nuclide is zinc-64.

The equation for this `beta^-`-decay is:

`""_29^64Cu ->` `""_30^64Zn` `+ ""_-1^0beta`