How do you solve # 12 + 3x = 30#?

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Answer 1 · 2016-07-28T02:21:43

#x = 6#

#color(coral)("Subtract 12 on both sides:")#

#cancel12+3x= 30#
#-cancel12# #color(white)(aa) -12#

12 cancels out on the left side, and when you subtract 12 from 30 on the right you get 18:

#3x= 18#

#color(green)("Divide both sides 3 to get x by itself.")#

#(cancel"3"x)/cancel3=(18)/3#

Now you are just left with #x# on the left side and 6 on the right side.

Thus,
#color(puroke)"x = 6"#