How do you solve for u in #2(u+3v)=w-5u#?

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Answer 1 · 2016-07-28T14:01:52

To solve for #u#, isolate #u# on one side of the equation.

First, let's use the distributive property to simplify the equation:

#2u+6v=w-5u#

Next, let's add 5u to each side:

#7u+6v=w#

Next, let's subtract 6v from each side:

#7u=w-6v#

Finally, divide each side by 7 to get our answer:

#u=(w-6v)/7#