What is the perimeter of a triangle with corners at #(3 ,3 )#, #(1 ,5 )#, and #(2 ,1 )#?

1 Answer
Shwetank Mauria
Jul 29, 2016

Perimeter is #9.1876#

Explanation:

As perimeter is sum of all the sides, let us find all the sides of triangle formed by #(3,3)#, #(1,5)# and #(2,1)#. This will be surely distance between pair of points, (which is given by #sqrt((x_2-x_1)^2+(y_2-y_1)^2)#. Hence the three sides are:

#a=sqrt((1-3)^2+(5-3)^2)=sqrt(4+4)=sqrt8=2.8284#

#b=sqrt((2-1)^2+(1-5)^2)=sqrt(1+16)=sqrt17=4.1231# and

#c=sqrt((2-3)^2+(1-3)^2)=sqrt(1+4)=sqrt5=2.2361#

Hence perimeter is #2.8284+4.1231+2.2361=9.1876#

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