How do you use the chain rule to differentiate #sin(e^(6x))#?
1 Answer
Jul 29, 2016
Explanation:
differentiate using the
#color(blue)"chain rule"#
#color(red)(|bar(ul(color(white)(a/a)color(black)(dy/dx=dy/(du)xx(du)/(dx))color(white)(a/a)|)))........(A)#
#rArry=sin(e^(6x))# let
#color(blue)(u=e^(6x))rArr(du)/dx=e^(6x).d/dx(6x)=6e^(6x)# and
#y=sincolor(blue)(u)rArr(dy)/(du)=coscolor(blue)(u)# substitute these values into (A) converting u into terms of x
#rArrdy/dx=cosu.6e^(6x)=6e^(6x)cos(e^(6x))#