How do you integrate ∫x3√x2−1 using substitution?
2 Answers
Jul 29, 2016
Explanation:
Let us take the subst.
Now,
Jul 29, 2016
Here is a third solution.
Explanation:
Let
so that
and
The integral becomes
=12[25u52+23u12]+C
=115[3u52+5u32]+C
=115u32[3u+5]+C
Back-substituting gets us
=115(x2−1)32[3(x2−1)+5]+C
=115(x2−1)32(3x2+2)+C