How do you solve using the completing the square method $9 x^{2} - 12 x - 2 = 0$ $9x^2-12x-2=0$ ?

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How do you solve using the completing the square method $9 x^{2} - 12 x - 2 = 0$ $9x^2-12x-2=0$ ?

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Answer 1 · 2016-07-29T15:13:30

$x = \frac{2 + \sqrt{6}}{3}$ $x=(2+sqrt(6))/3$
$x = \frac{2 - \sqrt{6}}{3}$ $x=(2-sqrt(6))/3$

Explanation:

$9 x^{2} - 12 x - 2 = 0$ $9x^2-12x-2=0$
or
${(3 x)}^{2} - 2 (3 x) (2) + 2^{2} - 2^{2} - 2 = 0$ $(3x)^2-2(3x)(2)+2^2-2^2-2=0$
or
${(3 x - 2)}^{2} = 6$ $(3x-2)^2=6$
or
$3 x - 2 = \pm \sqrt{6}$ $3x-2=+-sqrt(6)$
or
$3 x = 2 \pm \sqrt{6}$ $3x=2+-sqrt6$
or
$x = \frac{2 \pm \sqrt{6}}{3}$ $x=(2+-sqrt6)/3$
or
$x = \frac{2 + \sqrt{6}}{3}$ $x=(2+sqrt(6))/3$
or
$x = \frac{2 - \sqrt{6}}{3}$ $x=(2-sqrt(6))/3$

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How do you solve using the completing the square method $9 x^{2} - 12 x - 2 = 0$ $9x^2-12x-2=0$ ?

1 Answer

Explanation:

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How do you solve using the completing the square method 9x2−12x−2=09x^2-12x-2=0?

1 Answer

Explanation:

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How do you solve using the completing the square method $9 x^{2} - 12 x - 2 = 0$ $9x^2-12x-2=0$ ?