How do you solve by factoring # 2x^2+ 7x + 3=0#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Deepak G. Jul 29, 2016 #x=-3# #x=-1/2# Explanation: #2x^2+7x+3=0# or #2x^2+6x+x+3=0# or #2x(x+3)+1(x+3)=0# or #(x+3)(2x+1)=0# or #x+3=0# #x=-3#=======Ans #1# or #2x+1=0# or #2x=-1# or #x=-1/2#======Ans #2# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 21265 views around the world You can reuse this answer Creative Commons License