Question

How do you condense `ln2 + ln6 - (1/2)ln9`?

Answer 1

`ln2+ln6-(1/2)ln9=ln4`

Explanation:

We can use `lnx+lny=lnxy`, `lnx-lny=ln(x/y)` and `1/nlnx=ln(root(n)x)`

Hence, `ln2+ln6-(1/2)ln9`

= `ln(2xx6)-ln(sqrt9)`

= `ln12-ln3`

= `ln(12/3)=ln4`