How do you simplify #(6m+6n) / 2#?

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Answer 1 · 2016-07-31T13:22:57

#3(m+n)#

Write as #(6m)/2+(6n)/2#

Giving:#" "3m+3n#

But another way of writing this is #3(m+n)#

which means; multiply everything inside the bracket by 3

Answer 2 · 2016-07-31T16:41:27

#3(m+n)#.

#(6m+6n)/2=(6(m+n))/2=((3*2)(m+n))/2#

#=((3*cancel2)(m+n))/cancel2=3(m+n)#.