How do you find the range of #y=3x+4# for the domain {2,9, 11.5}?

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Answer 1 · 2016-07-31T19:02:56

Range#={10,31,38.5}#

Let #y=f(x)=3x+4, where, x in {2,9,11.5} =D_f, say#

The Range of #y = f# is denoted by #R_f#, and, is defined by,

#R_f={f(x) : x in D_f}#

#={f(2), f(9), f(11.5)}#

Here, #f(x)=3x+4 rArr f(2)=3xx2+4=10#

Similarly, #f(9)=31, and, f(11.5)=38.5#

Hence, #R_f={10,31,38.5}#