How do you simplify #2[(2*3) +10]div8#?

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Answer 1 · 2016-08-03T09:15:53

#4#

Start from the inner bracket. The multiplication did not really need to be in a bracket, because multiplication is done before addition.

#2[color(red)((2xx3))+10]div8#

=#2[color(red)(6)+10]div8#

Once we have #(2 xx16)/8#, there are many options for simplifying:

= #(2 xx16)/8 = (2 xxcancel16^2)/cancel8 = 2xx2 = 4#
OR

#(2 xx16)/8 = 32/8 = 4#

OR

#(2 xx16)/8 = (cancel2 xx16)/cancel8^4 = 16/4 = 4#