How do you differentiate # f(x)=ln(6x+8)# using the chain rule.?

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Answer 1 · 2016-08-04T10:01:37

#= 3/(3x+4) #

break it up as follows

#f(u) = ln (u)# and #u(x) = 6x +8#

#(df)/(dx) = (df)/(du)* (du)/(dx)#

#=d/(du) ln u * d/dx (6x + 8)#

#= 1/u * 6#

#= 1/(6x+8) * 6#

#= 3/(3x+4) #