Question #24930 Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer P dilip_k Aug 5, 2016 Explanation: Method-I #6x^3+3x^2y-2xy-y^2# #=3x^2(2x+y)-y(2x+y)# #=(2x+y)(3x^2-y)# Method-II #6x^3+3x^2y-2xy-y^2# #=6x^3-2xy+3x^2y-y^2# #=2x(3x^2-y)+y(3x^2-y)# #=(2x+y)(3x^2-y)# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1130 views around the world You can reuse this answer Creative Commons License