Question

How do you find the derivative of `sqrt(x-3)`?

Answer 1

`y^'=1/(2sqrt(x-3))`

Explanation:

`y=sqrt (u)" ; "y^'=u^'/(2sqrt(u))`

`y=sqrt(x-2)`

`u=x-3" ; "u^'=1`

`y^'=1/(2sqrt(x-3))`