How do you solve #1/3(n+1)=1/6(3n-5)#? Algebra Linear Equations Multi-Step Equations with Like Terms 1 Answer Deepak G. Aug 10, 2016 #n=7# Explanation: #1/3(n+1)=1/6(3n-5)# or #6/3(n+1)=3n-5# or #2(n+1)=3n-5# or #2n+2=3n-5# or #3n-2n=2+5# or #n=7# Answer link Related questions How do you solve multi step equations by combining like terms? How do you solve multi step equation #w + w + 12 = 40#? How do you solve #3p + 4p + 37 = 79#? How do you solve for f: #f-1+2f+f-3=-4#? How do you combine like terms? How do you combine like terms for #-7mn-2mn^2-2mn + 8#? How do you combine like terms for #3x^2 + 21x + 5x + 10x^2#? What is a term? How do you solve #3v+5-7v+18=17#? How do you solve for x in #5x + 7x = 72#? See all questions in Multi-Step Equations with Like Terms Impact of this question 5553 views around the world You can reuse this answer Creative Commons License